a cylinder whose height is two "-third" of its diameter ,has the same volume as a sphere of diameter 8 cm .find radius of the base of the cylinder
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Answer:
Radius of the base of the cylinder is 4cm.
Step-by-step explanation:
According to the question, it is given that :
height= 2÷3 of its diameter..(i)
If radius is r,then
Diameter=2r
eq(i)..becomes
h=(2×2r)÷3
h=4r÷3
Now, it is given that:
Volume of the cylinder = volume of sphere of radius 4cm
Sphere has diameter=8cm
so, radius= 4cm
Hence, πr²h= (4πr³)÷3
r²h= 4(4)³÷3
Put h= 4r÷3
(r²×4r)÷3= (4×64)÷3
r³=64
r=∛64
r= 4cm
Hence, we get the radius ie.,4cm.
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