Physics, asked by igjvkn, 11 months ago

A cylinder with a movable piston contains 3 moles of hydrogen at standard temperature and pressure. The walls of the cylinder are made of a heat insulator, and the piston is insulated by having a pile of sand on it. By what factor does the pressure of the gas increase if the gas is compressed to half its original volume?

Answers

Answered by Ahaan6417
11

Explanation:

The cylinder is completely insulated from its surroundings. As a result, no heat is exchanged between the system (cylinder) and its surroundings. Thus, the process is adiabatic.

Initial pressure inside the cylinder = P1

Final pressure inside the cylinder = P2

Initial volume inside the cylinder = V1

Final volume inside the cylinder = V2

Ratio of specific heats, γ = 1.4

For an adiabatic process, we have:

P1V1γ = P2V2γ

The final volume is compressed to half of its initial volume.

∴ V2 = V1/2

P1V1γ = P2(V1/2)γ

P2/P1 = V1γ / (V1/2)γ

= 2γ = 21.4 = 2.639

Answered by Anonymous
4

Explanation:

The cylinder is completely insulated from its surroundings. As a result, no heat is exchanged between the system (cylinder) and its surroundings. Thus, the process is adiabatic.

Initial pressure inside the cylinder = P1

Final pressure inside the cylinder = P2

Initial volume inside the cylinder = V1

Final volume inside the cylinder = V2

Ratio of specific heats, γ = 1.4

For an adiabatic process, we have:

P1V1γ = P2V2γ

The final volume is compressed to half of its initial volume.

∴ V2 = V1/2

P1V1γ = P2(V1/2)γ

P2/P1 = V1γ / (V1/2)γ

= 2γ = 21.4 = 2.639

Hence, the pressure increases by a factor of 2.639.

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