A cylinder with base radius 8 cm and height 2 is melted to form a cone of height 6 calculate the radius of the base and cone
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Answer:
radius = 8cm
height of cylinder = 2cm
let radius of cone be R
height of cone = 6cm
ATQ,
vol. of cylinder = vol. of cone
πr²h = 1/3 πR²H
8×8×2 = 1/3 R² ×6
64×2×3/6 = R²
R= √64
R = 8cm
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radius of cylinder =8cm
height =2 cm
height of cone =6 cm
volume of cylinder melted = volume of cone formed
πr^2h=1/3(πr^2h)
π*8*8*2=1/3(π*r^2*6)
(128*3)÷6=r^2
384÷6=r^2
64=r^2
8cm =r
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