Question

A cylinder with base radius of 8 cm and height of 2 cm is melted to form a cone of height 6 cm. The radius of the cone is
(a)4 cm
(b)5 cm
(c)6 cm
(d)8 cm

Answer 1

HOLA!!!

Volume of cylinder=

$\pi {r}^{2} h$

$= 128\pi \: cm {}^{3}$

Let us take the radius of the cone and cylinder as 'r'cm.

Then according to the question,

$(1 \div 3)\pi {r}^{2} h = 128\pi$

${r}^{2} =( 128 \times 3) \div 6$

${r}^{2} = 64$

$r = \sqrt{64}$

$r = 8 \: cm$

HOPE IT HELPS UHH #CHEERS

Answer 2

Heya!

Here is ur answer..

_________________________

Given that, a cylinder is melted to form a cone.

Therefore,

Volume of cylinder = Volume of Cone

Radius of cylinder = 8cm

Height of cylinder= 2cm

Height of cone = 6cm

Now,

Volume of cylinder = Volume of cone

pi r^2h = 1/3 x pi r^2h

r^2h = 1/3 x r^2h

8^2 x 2 = 1/3 x r^2 x 6

64 x 2 = 2 r^2

128 = 2r^2

r^2 = 128/2

r^2 = 64

r = root 64

r = 8 cm

Therefore, the radius of cone = 8cm

Hope it helps