Question

a cylinder with radius 5 units and height 7 units has volume V.in terms of V ,what is the volume of cylinder with radius 2.5units and height 7 units please answer it step by step I will mark as brainlist answer​

Answer 1

Step-by-step explanation:

$v1 = \pi {r}^{2} h \\ v2= \pi {x}^{2} h \\ v1 = \pi \times {5}^{2} \times 7 \\ v2 = \pi \times {2.5}^{2} \times 7 \\ \frac{v1}{v2} = \frac{\pi \times {5}^{2} \times 7}{\pi \times {2.5}^{2} \times 7 } \\ \frac{v1}{v2} = { \frac{5}{2.5} }^{2} \\ \frac{v1}{v2} = {2}^{2} \\ \frac{v1}{v2} = 4 \\ v2= \frac{v1}{4}$

plzz mark as brainliest answer

Answer 2

Answer:

Step-by-step explanation:

\begin{gathered}v1 = \pi {r}^{2} h \\ v2= \pi {x}^{2} h \\ v1 = \pi \times {5}^{2} \times 7 \\ v2 = \pi \times {2.5}^{2} \times 7 \\ \frac{v1}{v2} = \frac{\pi \times {5}^{2} \times 7}{\pi \times {2.5}^{2} \times 7 } \\ \frac{v1}{v2} = { \frac{5}{2.5} }^{2} \\ \frac{v1}{v2} = {2}^{2} \\ \frac{v1}{v2} = 4 \\ v2= \frac{v1}{4} \end{gathered}v1=πr2hv2=πx2hv1=π×52×7v2=π×2.52×7v2v1=π×2.52×7π×52×7v2v1=2.552v2v1=22v2v1=4v2=4v1