Question

a cylinderical tank7m diameter contains water a depth of 4 m. find the total area of the wet surface π3•14​

Answer 1

Answer:

Answer is 126.5 sq.m

Step-by-step explanation:

Given, 2r=7

⇒r=7/2;h=4

Area of wetted surface = CSA of cylinder ABCD + Area of base (Circle)

=2πrh=πr

2

=πr(2h+r)

=

7

22

×

2

7

(8+3.5)

=11×11.5=126.5 sq. m