Question

A cylinderical vessel with diameter 42cm contains sufficient water to submerge a rectangular solid of iron of dimensions 24cm *16.5cm*12cm.find the rise in the level of water when the solid is completely submerged.

Answer 1

Volume of rectangular solid of iron-24cm*16.5cm*12cm= 4752$cm^{3}$

We know that volume of rectangular solid of iron= volume of water displaced

Volume of water displaced= 4752$cm^{3}$

To find rise of level of water, we equate the formula with the volume-
$\pi r^{2} h$=4752
(22*21*21*h)/7=4752
(22*21*3*h)=4752
1386h=4752
h=3.43 $cm^{3}$ (approx.)