A cylinderical wire is stretched to increase its length by 10%.calculate the percentage increase in resistance
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Answer:
21%
explanation:
R=rho× L/A
when we are stretching both l and A will change.
But in this question increase in length is only given. So, we convert the above the equation from 2 variable to 1 variable by multiplying l on numerator and denominator of R. H. S
=>
R=rho× L^2/V [ V= A×L]
when stretching volume won't change.
Ri=rho( L^2/V)
Rf= rho (L+10/100L)^2/V
Rf= rho (11/10L)^2/V
Rf= rho (121/100L^2) /V
Rf/Ri=121/100
(Rf/Ri)-1 = (121/100)-1
(Rf-Ri)Ri= 21/100
(Rf-Ri) /Ri × 100= 21%
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