Question

A cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. A cylindrical basin is 2 feet tall and has a diameter of 5 feet.
If the basin is completely filled with water, how much water will it hold? Round the answer to the nearest tenth of a foot.
ft3

Answer 1

Cylinder will hold water = 39.26 ft³

Given:

A cylindrical basin is 2 feet tall and has a diameter of 5 feet.

The basin is completely filled with water.

To find:

How much water will it hold?

Formula used:

Volume of cylinder = $\frac{\pi}4}$ × (Diameter)²×Height

Explanation:

A cylindrical basin is 2 feet tall and has a diameter of 5 feet.

That is,

Height of cylinder = 2 feet

Diameter = 5 feet.

Volume of cylinder = $\frac{\pi}4}$ × (Diameter)²×Height

                                =  $\frac{\pi}4}$ × 5² × 2

                                = 39.26 ft³

So, Cylinder will hold water = 39.26 ft³

To learn more:

1)The diameter of a cylindrical tank is 24.5 and depth is 8 cm. how many metric tons of water will it hold.​

https://brainly.in/question/8359406

2)A cubical water tank is of side 2m how many litres of water can it hold

https://brainly.in/question/1532921

         

Answer 2

The correct answer is 39.3