A CYLINDRICAL BLOCK OF BREEZE HAS A MASS 20 GRAMS ITS HEIGHT 5.0 CENTI METERS ITS DENSITY 8.7 CENTIMETER CUBE THEN THE AREA O F THE CROSS SECTION OF THE BLOCK IS
OPTIONS:
1. 670 CENTIMETER SQUARE
2.67 CENTIMETER SQUARE
3. 6.7 CENTIMETER SQUARE
4. 0.67 CENTIMETER SQUARE
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Given data:-
Height of the cylinder, h=5cm
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Answer:-
Density of the cylinder, d =M/v = 8.7g/cm³
Mass of the cylinder, M = 20g
Volume of the cylinder, v = πr²h
Step-by-step explanation:-
=> d = M / v
=> d = M /πr²h
=> r² = M/dπh
=> r² = 20/ (3.14×8.7×5)
=> r² = 0.1464
=> r = 0.382cm
Therefore, cross section area of the given cylinder, A = πr² = 3.14 × 0.1464
= 0.67cm²
Hence, the cross sectional area of the given cylinder is 0.67cm²
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
HOPE THIS HELPS YOU...
Given data:-
Height of the cylinder, h=5cm
HOLA MATE !!!
HOPE THIS HELPS YOU...
Answer:-
Density of the cylinder, d =M/v = 8.7g/cm³
Mass of the cylinder, M = 20g
Volume of the cylinder, v = πr²h
Step-by-step explanation:-
=> d = M / v
=> d = M /πr²h
=> r² = M/dπh
=> r² = 20/ (3.14×8.7×5)
=> r² = 0.1464
=> r = 0.382cm
Therefore, cross section area of the given cylinder, A = πr² = 3.14 × 0.1464
= 0.67cm²
Hence, the cross sectional area of the given cylinder is 0.67cm²
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
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