A cylindrical block of wood of mass M is floating n water with its axis vertica. It is depressed a little and then released. Show that the motion of the block is simple harmonic and find its frequency.
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PHYSICS
A cylindrical block of wood of mass m, radius r & density p is floating in water with its axis vertical. It is depressed a little and then released. If the motion of the block is simple harmonic. Find its frequency.
A .
2π1mπr2pg
B .
2π1mπr3pg
C .
4π1mπr2pg
D .
4π1mπr3pg
December 26, 2019Afeera Dhurwey
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ANSWER
Suppose a height h of the block is dipped in the water in equilibrium position. If r be the radius of the cylindrical block, the volume of the water displaced =πr2h. For floating in equilibrium,
πr2hpg=W .........(i)
where p is the density of water and W the weight of the block. Now suppose during the vertical motion, the block is further dipped through a distance x at some instant. The volume of the displaced water is πr2(h+x) pg vertically upward.
Net force on the block at displacement x from the equilibrium position is
F=W−πr2(h+x)pg=W−πr2hpg−πr2pxg
Using (i) F=πr