Question

A cylindrical bowl of internal dimater 18cm and hight is 15cm full of liqudif the whole of loquid is filled in small cylindrical bottle 3cm and hight 4cm eacb bottle is sold for rs-5 find the amount earmed

Answer 1

$\bold{Given}$

A cylindrical bowl have diameter = 18 cm

So, its radius = $\mathsf{ \frac{18}{2} = 9}$

Height = 15cm

$\huge \boxed{ \mathsf{VOLUME = \pi {r}^{2} h}}$

So, on placing values

$\mathsf{VOLUME = \dfrac{22}{7} \times {9}^{2} \times 15}$

$\huge \boxed{ \mathsf{VOLUME =3818.57 cm^{2}}}$

$\underline \bold{According \: to \: question }$.

The liquid in the the cylindrical bowl is filled in small cylindrical bottles of

Radius = 3cm

Height = 4cm

So,

$\huge \boxed{ \mathsf{VOLUME \: OF \: ONE \: BOTTLE = \pi {r}^{2} h}}$

$\mathsf{VOLUME = \dfrac{22}{7} \times {3}^{2} \times 4}$

$\huge \boxed{ \mathsf{VOLUME =113.14 cm^{2}}}$

Since,

$\boxed{ \mathsf{Number \: of \: bottles = \dfrac{Volume \: of \: cylindrical \: bowl}{Volume \: of \: one \: cylindrical bottle}}}$

$\mathsf{Number \: of \: bottles = \dfrac{3818.57}{113.14}}$

$\boxed{ \mathsf{Number \: of \: bottles =33.7 or 34 \: bottles}}$

◼One bottle costs = Rs.5

◼So, cost of 34 bottles = 34 ×5

$\huge{\boxed{ \mathsf{Rs .170}}}$