Question

A cylindrical bucket , 28 cm in diameter and 72 cm high is full of water. The water is emptied into a rectangular tank, 66 cm long and 28 cm wide. Find the height of the water level in the tank

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Answer 1

Answer

24 cm

Step-by-step-explaination

☞ Given :

cylindrical bucket

• Diameter = 28 cm

• Height = 72 cm

rectangular tank

• Length = 66 cm

• Width = 28 cm

☞ To find :

• Height of the waTer level in the tank.

☞ Solution :

We know that ,

$\boxed{\sf \: Volume \: of \: cylinder = \pi \: {r}^{2} h}$

So ,

$\sf \implies \: Volume \: of \: water \: in \: tank \: = \pi \: \times \: {14}^{2} \times 72$

$\sf \implies \: Volume \: of \: water \: in \: tank \: = \frac{22}{7} \times 196 \times 72$

$\sf \implies \: Volume \: of \: water \: in \: tank \: = \frac{22}{7} \times \: 14112$

$\sf \implies \: Volume \: of \: water \: in \: tank \: = 44352 {cm}^{3}$

${ \boxed {\sf{ Volume \: of \: water \: in \: rectangular \: tank \: = length \times breadth \times height}}}$

$\sf \: Volume \: of \: water \: in \: tank \: = \: Volume \: of \: water \: in \: cylinder$

$\implies \sf \: 44352 = 66 \times 28 \times height$

$\implies \sf \: 44352 = 1848h$

Let's flip the equation !

$\sf \implies \: 1848h = 44352$

$\sf \implies \: h = \dfrac{44352}{1848}$

$\sf \implies \: h = 24cm$

The height of tank will be 24cm .

What you need to know ?

• You need to know volumes

• you need to know framing of a question into equation