Question

A cylindrical bucket 32 cm high and 18 cm of radius of the base is filled with sand. This bucket is emptied on the

ground and a conical heap of sand is formed. If the height of the conical heap is 24 cm. Find the radius and slant height of the heap​

Answer 1

Answer:

ok

Step-by-step explanation:

a cylindrical bucket 32 cm high and 18 cm of radius .

32 + 18

50

then ,

50 - 24

26

26 cm is the radius and slant height of the heap .

Answer 2

Answer:

Radius of cylinder = 18 cm,

height = 32 cm

Height of cone = 24 cm

= πr²h

= 22/7 x 18²x 32

Volume of cylinder Volume of cone = Volume of cylinder

Volume of cone

1/3πr²x 24

Hence,

radius of cone can be calculated as follows:

$r {}^{3} = \frac{ 3 \times \pi \times 18 {}^{2} \times 32}{\pi \times 24}$

or, r²= 18² x 2²

or,r = 36cm

Now, slant height of conical heap can be calculated as follows:

$l = \sqrt{h} {}^{2} + r {}^{2}$

$= \sqrt{24 {}^{2} + 36 { }^{2} }$

$= \sqrt{1872}$

$= 36 \sqrt{13cm}$