Question

A cylindrical bucket of diameter 28cm and height 20 CM was full of sand. When the sand in the bucket was poured on the ground the sand got converted into a shape of cone.
if the height of the cone was 14 cm what was the base area of the cone.

Answer 1

Given,

Diameter of Cylinder = 28 cm
Radius of Cylinder = d/2 = 28/2 cm = 14 cm
Height = 20 cm

=> Volume of Cylinder = Volume of Cone

=> πr^2h = 1/3 πr^2h

=> 22/7 x 14 x 14 x 20 = 1/3 x 22/7 x r^2 x 14

=> 12320 cm^3 = 14.6 r^2

=> r^2 = 12320/14.6

$= > \: r \: \: = \sqrt{843.8}$

=> r = 29.04 cm

Now,

Base area of Cone = πr^2

=> Area = (22/7 x 29.04 x 29.04) cm^2

=> Area = 2650.43 cm^2

Answer 2

here is ur answer....

Diameter of Cylinder = 28 cm

Radius of Cylinder = d/2 = 28/2 cm = 14 cm

Height = 20 cm

=> Volume of Cylinder = Volume of Cone

=> πr^2h = 1/3 πr^2h

=> 22/7 x 14 x 14 x 20 = 1/3 x 22/7 x r^2 x 14

=> 12320 cm^3 = 14.6 r^2

=> r^2 = 12320/14.6

= > \: r \: \: = \sqrt{843.8}=>r=

843.8

=> r = 29.04 cm

Now,

Base area of Cone = πr^2 I

=> Area = (22/7 x 29.04 x 29.04) cm^2

=> Area = 2650.43 cm^2..

STAY BLESSED ❤️ ❤️