a cylindrical bucket with base radius 15cm is filled with water up to a height of 20cm a heavy iron spherical ball of radius 9cm is dropped into the bucket to submerge completely in the water find the increase in the level of water. ( answer=4.32cm)
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Volume of water displaced = volume of spherical ball
πr^2h = (4/3)πR^3
225h = (4/3)729
225h = 972
h = 4.32 cm
hence the increase in level of water is 4.32 cm
πr^2h = (4/3)πR^3
225h = (4/3)729
225h = 972
h = 4.32 cm
hence the increase in level of water is 4.32 cm
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