Question

A cylindrical can off internal diameter 12 cm contains some water when A solid sphere Of diameter 9 cm is placed in it it is completely immersed find a rise in water level if no water flows out

Answer 1

radius of cylinder is equals to 6 CM now according to question volume of can is = Pi R square h
22/7×36×h
so
no volume of solid sphere=4/3×22/7×4.5^3
SO the volume of cylinder is =volume of spare so
22/7×36×h=4/3×22/7×4.5^3
h=0.375cm ans please mark me as brainlist

Answer 2

The rise in the  water level of the cylindrical can is 3.375 cm.

• Given:

Internal diameter of the cylindrical can that contains some amount of water = 12 cm

∴Internal radius = 6 cm

Diameter of the solid sphere = 9 cm

∴Radius of the solid sphere = 4.5 cm

• Volume of the solid sphere = (4/3)πr³

Volume = (4/3)π(4.5)³

Volume = 121.5π cubic cm

• Now, the given solid sphere is completely immersed in the cylinder.
• Therefore, the rise in the water level after immersing the solid sphere is equal to the volume of the solid sphere.
• Let the rise in water be equal to h.
• Therefore, Volume of water increased in the can = Volume of the solid sphere

Volume of the cylinder = πr²h

πr²h = 121.5π

6×6×h = 121.5

h = 3.375 cm

• The rise in the water level in the can is 3.375 cm.