Physics, asked by jayantyadav614, 10 months ago

A cylindrical! Capacitor of outer radius b.2hat would be the inner radius of the capacitor so that for a applied potential difference,the electric field strength very close to the inner surface is minimum

Answers

Answered by bishaldasdibru
0

Answer :

To minimize the electric field strength close to the inner surface of a cylindrical capacitor with outer radius b, the inner radius should be equal to zero. This will result in the highest capacitance value, leading to the lowest electric field strength.

Explanation :

To determine the inner radius of the cylindrical capacitor so that the electric field strength close to the inner surface is minimum, you need to consider the capacitance formula for a cylindrical capacitor. The capacitance of a cylindrical capacitor is given by C = 2πε0 ln(b/a), where C is the capacitance, ε0 is the permittivity of free space, b is the outer radius, and a is the inner radius. To minimize the electric field strength close to the inner surface, we need to maximize the capacitance. To maximize the capacitance, we need to minimize the difference between the outer radius and inner radius (b/a). This means that the inner radius must be as close as possible to the outer radius. So, the inner radius of the capacitor should be b.

To know more about the concept please go through the links :

https://brainly.in/question/39827740

https://brainly.in/question/17342808

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