Question

a cylindrical conducter of length L and area of cross section A has resistance R . Another conductor of same material has length 2l and resistance R so it's area os cross section will be

Answer 1

Answer:

2A

Explanation:

As we know..

1st cylinder R= ¶ L 1 / A1. ( ¶ as roh)

2nd cylinder R = ¶ 2L1/X ( length double and X to find)

R will same for both so if Length will b double to ratain R same must double the A.

Answer 2

New area become two times of the initial area.

Explanation:

The resistance of a conductor is given by :

$R=\rho \dfrac{l}{A}$ .......(1)

l is length of conductor

A is area of cross section

Another conductor of same material has length 2l and resistance R. New resistance is given by :

$R=\rho\dfrac{2l}{A'}$  .......(2)

Dividing equation (1) and (2) we get :

$\dfrac{R}{R}=\dfrac{l}{A}\times \dfrac{A'}{2l}\\\\1=\dfrac{A'}{2A}\\\\A'=2A$

New area become two times of the initial area.

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Resistance

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