A cylindrical conductor of length land uniform area of cross section. A has resistance R. Another conductor of length 2l and resistance R of the same material has area of cross section.
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Explanation:
the the resistance of a wire can be expressed and has
R= p l/A
A= p L/R
p - resistivity the factor in the resistance which take into account the natural of the material is resistivity
L= length of the conductor
A= area of a cross section of the conductor
from this relation we observed that the length is directly proportional to the resistance and the area of cross-section is inversely proportional to the resistance in this case the length of the conductor is doubled 2L and so that resistance will be to 2r from the resistance to remain the same has R1 the area of cross section also doubled as 2A to a hence the area of cross section is 2A
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