Math, asked by chodharypriya45, 8 months ago

A cylindrical container is 84 cm high and has base radius of 4.2 cm. Find the cost of painting its curved surface at the rate of ₹8 per 100 sq cm.
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Answers

Answered by sumansharma91
46

Answer:

₹177.408

Step-by-step explanation:

Height of cylinder=84cm

Radius of base=4.2cm

CSA of cylinder=2πrh

=2×22/7×4.2×84

2×22/7×42/10×84

22176/10

Cost of painting=₹8×22176/10×100

=177408/1000=₹177.408

Answered by JeanaShupp
12

The cost of painting its curved surface is Rs 177.25.

Explanation:

Curved surface area of a cylinder =2\pi (radius)\times (height)

Given : Height of cylinder = 84 cm

radius of cylinder = 4.2 cm

Then , the curved surface area = 2(3.14) (4.2)\times (84)

=2215.584\ \text{sq cm}

Now , the  cost of painting its curved surface at the rate of ₹8 per 100 sq cm would be =2215.584\times\dfrac{8}{100}

=177.24672\approx177.25

Hence,  the cost of painting its curved surface is Rs 177.25.

# Learn more :

Find the total surface area and the volume of a closed cylindrical container with radius 5 cm and a height of 34 cm.

https://brainly.in/question/2704059

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