A cylindrical container is filled with oil to a depth of 32 cm. if the pressure exerted at the base of the container is known to be 2560 pa then, how much is the density of the oil?
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Explanation:
pressure P=density* acceleration due to gravity *height
2560=density *10 *32/100
density=25600 /32=800
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Answer:
The static pressure of the fluid can be calculated by the formula. The dencity of the given oil is 815 kg/m3.
The static pressure of the fluid can be calculated by the formula,
P = Ro g h
Where,
Ro = density [kg/m³] =?
g = gravity acceleration = 9.81 m/s²
h = depth = 32 cm = 0.32 m
P = pressure = 2560 pa
put the values in the formula,
2560 = Ro x 9.18 x 0.32
Ro = 815 kg/m3
Therefore, the dencity of the given oil is 815 kg/m3.
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