A cylindrical container is to be made of tin sheet. The height of the container is 1 m and its diameter is 70cm.If the container is open at the top and the sheet costs ₹300 per m2 , find the cost of the tin sheet for making the container
Answers
Answered by
28
Gɪᴠᴇɴ :-
- Cylinder container is made of tin sheet
- Container is open at the top and the sheet costs ₹300 per m²
- Height of the container = 1m
- Diameter of container = 70cm
- Radius of container = 70/100 × 2 = 0.35 m
ᴛᴏ ғɪɴᴅ :-
- The cost of the tin sheet for making the container
sᴏʟᴜᴛɪᴏɴ :-
☞As we know that
✚ Total surface area of cylinder
→ Curved surface area of cylinder + area of two circles
→ 2πrh + 2πr²
- Container is open at the top.
✚ So, area of container
➪ 2πrh + πr²
➪ 2 × 22/7 × 0.35 × 1 + 22/7 × 0.35 × 0.35
➪ 2 × 22 × 0.05 + 22 × 0.05 × 0.35
➪ 44 × 0.05 + 0.385
➪ 2.2 + 0.385
➪ 2.585 m²
- Therefore, the area of the tin sheet for making the container is 2.585m²
✚ Now, the cost of the tin sheet for making the container
- Cost of 1m² sheet = Rs.300
➪ 2.585 × 300
➪ Rs.775.5
Hence,
- The cost of the tin sheet is Rs.775.5
Anonymous:
Perfect explanation :D
Answered by
17
Given :-
- The height (h) of the container is 1m. and it's diameter (d) is 70cm. The container is open at the top and the sheet costs ₹300 per m².
To Find :-
- The cost of the tin sheet for making the container.
Solution :-
____________________
- Diameter (d) = 70cm
=> r = d/2
=> r = 70/2
=> r = 35cm.
=> r = 35/100 m
=> r = 0.35 m.
____________________
Now,
- Area of tin sheet required = Curved surface area of cylinder + Area of base
=> Area of tin sheet required = 2πrh + πr²
=> Area of tin sheet required = 2×22/7× 0.35 ×1 + 22/7 × (0.35)²
=> Area of tin sheet required = 44 × 0.05 × 1 + 22/7 × 0.1225
=> Area of tin sheet required = 2.2 + 0.385
=> Area of tin sheet required = 2.585m².
____________________
- The cost of tin sheet for making container = 2.585m² × ₹300/m²
=> The cost of tin sheet for making container = ₹775.5 .
Hence,
- The cost of tin sheet for making container is ₹775.5.
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