Question

A cylindrical container of diameter 30 cm consists of a liquid of mass 18 kg. Calculate the pressure exerted by the liquid on the bottom of the container

Answer 1

first of all pressure is force upon area

P=F/A

due to gravity of the earth force on liquid of mass 18kg is 180 N

and area of base of container is πr^2 = π(15/100)^2= 0.07 m^2

now from above formula:

P= 180/0.07 N/m^2

P= 2571 N/m^2

Answer 2

Answer:

The strain exerted through the liquid on the backside of the container is 2493.1 Pa.

Explanation:

To calculate the stress exerted by way of the liquid on the backside of the container, we want to use the method for pressure:

                  Pressure = Force/Area

The pressure right here is the weight of the liquid, which is equal to its mass extended via the acceleration due to gravity (g).

                   Force = mass x g

Here, mass = 18 kg, and

        acceleration due to gravity (g) = 9.8 m/$s^2$ (standard value).

Force = 18 kg x 9.8 m/s^2

          = 176.4 N

Now, we want to calculate the location of the backside of the container. Since the container is cylindrical, the backside is a circle with diameter 30 cm.

Diameter = 30 cm

   Radius = Diameter/2

   Radius =  15 cm

  Radius = 0.15 m

Area of circle = π x $radius^2$

                      = π x (0.15 m)$.^2$

                      = 0.0707 $m^2$

Therefore, the stress exerted by using the liquid on the backside of the container is:

Pressure = Force/Area

                = 176.4 N / 0.0707 $m^2$

                = 2493.1 Pa

Therefore, the strain exerted through the liquid on the backside of the container is 2493.1 Pa.

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