Physics, asked by veenajetpuriya8559, 10 months ago

A cylindrical container of radius r = 1 m, wall thickness 1 mm is filled with water up to a depth of 2 m and suspended along its upper rim. The density of water is 1000 kg/m3 and acceleration due to gravity is 10 m/s2. The self-weight of the cylinder is negligible. The formula for hoop stress in a thin-walled cylinder can be used at all points along the height of the cylindrical container.

Answers

Answered by Anonymous
1

Radius of the cylindrical container = 1m (Given)

Thickness of the wall = 1mm (Given)

Depth of the water = 2m (Given)

Density of water = 1000 kg/m³ (Given)

Acceleration due to gravity = 10 m/s². (Given)

Axial strain in the cylinder will be produced due to the longitudinal axial stress and also due to the lateral stress

Therefore, the axial strain will be –  

Ee = 1/Y ( ∝ a- ∝ e/m)

= 1/ 100 × 10³. ( 5 – 10 × 0.3)

= 2  × 10`-5

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