a cylindrical container with diameter of base 56 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 32cm×22cm×14cm. find the rise in the level of the water when the solid is completely submerged. explain with making a diagram too
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Answered by
72
Answer:
The rise in water level will be 4 cm
Step-by-step explanation:
when the iron block will be submerged in the water, then the volume of water rise will be equal to the volume of the iron block.
volume of the iron block = 32 x 22 x 14 = 9856 cm³
Given the diameter of the cylindrical container = 56 cm
=> radius of the cylindrical container = 56/2 = 28 cm
Let the rise in water level be h cm
=> volume of water raise = πr²h
= 22/7 x 28 x 28 x h
= 2464 h cm³
Hence ,
2464 x h = 9856
=> h = 9856/2464 = 4 cm
Hence the rise in water level will be 4 cm
Answered by
14
Answer: The rise in the water level = 4cm
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