Question

A cylindrical dog water bowl is 10 inches wide and 4 inches deep. How much plastic is needed to make the bowl?
(A) 125.6 inches
(B) 204.1 inches
(C) 282. 6 inches
(D) 300.6 inches

Answer 1

Answer:

Option (C)

Step-by-step explanation:

Given :-

A cylindrical dog water bowl is 10 inches wide and 4 inches deep.

To find :-

The plastic is needed to make the bowl.

Answer :-

Given that

Width of the cylindrical dog water bowl

= 10 inches

Diameter of the water bowl = 10 inches

We know that

Radius = Diameter /2

Radius of the bowl = 10/2 = 5 inches

Depth of the water bowl = 4 inches

Height of the bowl = 4 inches

To make a water bowl ,we have to find the total surface area of the bowl.

We know that

Total surface area of a cylinder

= 2πr(r+h) sq.units

We have,

r = 5 inches

h = 4 inches

Total surface area of the bowl

= 2×3.14×5(5+4) sq.inches

= 6.28×5(9) sq.inches

= 6.28×45 sq.inches

= 282.6 sq.inches

Answer:-

The plastic is needed to make the dog water bowl is 282.6 sq.inches

Used formulae:-

→ Radius = Diameter /2

→ Total surface area of a cylinder = 2πr(r+h) sq.units

• r = radius
• h = height
• π = 22/7 = 3.14