a cylindrical garden roller is 75cm.long and its radius is 14cm.how many revolution will it make to level an area of 9900cm2
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Answer:
Therefore the no. of revolutions are 1.5.....
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The total number of revolution is 1.5
Given data :
Length of the roller = 75 cm
Radius of the roller = 14 cm
Garden's area = 9900 cm²
So,
Curved surface are of the roller
= 2 × π × r × h
= 2 × 22/7 × 14 × 75
= 2 × 22 × 2 × 75
= 88 × 75
= 6600 cm²
Number of revolutions = (9900/6600) = 1.5 (answer)
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