Question

A cylindrical glass of radius 7 cm is filled juice up to height of 16 cm .when carefully observed the bottom of glass is covered by a transparent cone of height 3 cm and 7 cm. (i) what is actual volume of juice? (ii) In which category you will put the seller.

Answer 1

BRO THE RADIUS OF THE CONE IS 7CM.
THEN THE ANSWER WILL BE AS FOLLOW.
BRO I THINK THIS WILL HELP U IF HELP THEN PLS THANKS ME AND MARK ME AD BRAINLIST.

Answer 2

Radius of cylindrical = 7cm

Height = 16cm

$volume \: \: of \: cylidrical \: part = \pi {r}^{2} h \\ \: \: \: \: = \frac{22}{7} \times 7cm \times 7cm \times 16cm \\ \: \: \: \: = 2464cm^{3}$

Radius of cone = 7cm

Height of cone = 3cm

$volume \: of \: cone = \frac{1}{3} \pi {r}^{2} h \\ \: \: \: \: \: \: = \frac{1}{3} \times \frac{22}{7} \times 7 cm\times 7cm \times 3cm \\ \: \: \: \: = 154 {cm}^{3} \\ Actual \:Volume\: of \:glass =2464cm ^{3} -154 {cm}^{3 } \\ \: \: \: \: \: \: \: \: \: = 2310 {cm}^{3} \\ (ii)we \: will \: put \: the \: seller\: in \: \\ category \: of \: cheater.$