Question

A cylindrical glass with diameter 20cm has water to a height of 9cm. A small cylindrical metal of radius 5cm and height 4cm is immersed it completely. calculate the raise of the water in the glass ?

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Answer 1

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Hey friend!!

Question:

A cylindrical glass with diameter 20cm has water to a height of 9cm. A small cylindrical metal of radius 5cm and height 4cm is immersed it completely. calculate the raise of the water in the glass ?

Solution:

{The Diagram of thid question makes you more understanding.}

««« Follow the question with diagram »»»

★Read the question carefully. In the question diameter is given. According to Mathematics Diameter means ' half (or) divided by 2.'

So,

Diameter = 20cm

$= \frac{20}{2}$

$= 10 \: cm$

★Now, you can able to understand, why I have drawn the radius as 10cm in the diagram

★ I hope you can able to understand..

Given:

For water:

Radius = 10cm

height = ?

For cylindrical metal:

Radius = 5cm

Height = 4cm

By Using the clue: ( v = v )

$\color{red}Volume \: of \: water \: raised \: = volume \: of \: cylindrical \: Metal$

$\pi {r}^{2} h \: = \: \pi {r}^{2} h$

$10 \times 10 \times h \: = \: 5 \times 5 \times 4$

$h = \frac{5 \times 5 \times 4}{10 \times 10}$

$h = \frac{ 1 \times1 \times 4 }{2 \times 2}$

$h = \frac{1 \times 1 \times 1}{1 \times 1}$

$h \: = 1 \: cm$

$\color{blue}Therefore \: the \: raise \: of \: water \\ \color{blue} in \: the \: glass \: is \: \color{red}1cm$