Question

A cylindrical iron pillar 49 cms high and 6 cms in radius is surmounted by a cone 14 cms high. The volume of pillar is .

Answer 1

Answer: The volume of pillar is 6072 cm^3.

Step-by-step explanation:

From the configuration, we know that:

The volume of the pillar = volume of cylindrical iron + volume of cone

Now,

Volume of cylindrical iron = pi*R^2H  (where r= radius, and h= height of cylindrical iron)

We have

R= 6 cm, H= 49 cm

So,

The volume of cylindrical iron = 22/7*6^2*49 (putting the given values)

   = 22/7*6*6*49

   = 22*6*6*7

   = 5544 cm^3

Now,  

Volume of cone = 1/3*pi*R^2h  (Where R= radius of cone, h= height of cone)

We have,

R= 6 cm, h= 14cm

So,

The volume of cone= 1/3*22/7*6^2*14 (putting the given values)

 = 1/3*22*6*6*2

 = 22*2*6*2

 = 528 cm^3

So,

The volume of the pillar = 5544 + 528

= 6072 cm^3

Answer 2

Answer:

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