A cylindrical iron pipe is 21m long and it's external diameter is 8cm. if the thickness of the pipe is 1cm and iron weighs 8g/cm cube. find the weight of the pipe
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Given: External diameter = 8 cm
Then
External radius = 4 cm,
Internal radius = 4-1=3 cm.
∴Volume of iron = {(22/7)* [(4)2 - (3)2] x 21} cm3= {(22/7)*7*1*21} cm3 = 462 cm3
⇒Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
HOPE , IT HELPS ...
Given: External diameter = 8 cm
Then
External radius = 4 cm,
Internal radius = 4-1=3 cm.
∴Volume of iron = {(22/7)* [(4)2 - (3)2] x 21} cm3= {(22/7)*7*1*21} cm3 = 462 cm3
⇒Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
HOPE , IT HELPS ...
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