A Cylindrical metal bar 50cm long and 6cm in diameter is pulled out to form a wire of diameter 3mm.
a. What length is the wire
b. How does the curved surface area of the wire Compare with that of the bar.
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Answer:
Let the length be l
volume of wire= ¥(3/20)^2 x l
Volume of bar = ¥ x 3^2 x 50cm
Equate both volume
¥ x 9x/400 = ¥ x 9 x 50
cross multiply
¥9x = 400 x 9¥ x 50
x=20000 x 9¥/9¥
x =20000cm
20000cm = 200m
thus length = 200m
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