a cylindrical milk steel storage tank has 4.2m as diameter and is 4.5 m high . [a] find quantity of milk it can contain. [b] how much steel sheet was actually used to make this closed tank , if 1/7 of steel sheet was wased in making the tank
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Given = diameter = 4.2 m so radius = 2.1 m
height = 4.5 m
[a] Quantity of milk it can contain so we need to calculate the volume of the tank
Volume of cylinder = πr^2h
= 22/7*2.1*2.1*4.5
= 22*0.3*2.1*4.5
= 6.6*9.45
= 62.37 cu. m
[b] how much steel was used so we need to calculate total surface area of the tank
T.S.A of cylinder = 2πr(r+h)
= 2*22/7*2.1(2.1+4.5)
= 2*22*0.3(2.1+4.5)
= 13.2*6.6
= 87.12 sq. m
height = 4.5 m
[a] Quantity of milk it can contain so we need to calculate the volume of the tank
Volume of cylinder = πr^2h
= 22/7*2.1*2.1*4.5
= 22*0.3*2.1*4.5
= 6.6*9.45
= 62.37 cu. m
[b] how much steel was used so we need to calculate total surface area of the tank
T.S.A of cylinder = 2πr(r+h)
= 2*22/7*2.1(2.1+4.5)
= 2*22*0.3(2.1+4.5)
= 13.2*6.6
= 87.12 sq. m
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