A cylindrical of radius 10.5 cm and height 70 cm was full of water and poured it into a rectangle tank containing water to a height 70 cm. Find the new level of water base of the tank is 80 cm by 60 cm and height 1 m
Answers
Answer:
Given that height of the cylinder h = 12 m
Given that diameter of the cylinder d = 7 m
we know that radius r = d/2 = 7/2 = 3.5 m
volume of cylindrical tank is given by
V=\pi r^2hV=πr
2
h
V=3.14 *3.5^2*12 = 461.58V=3.14∗3.5
2
∗12=461.58 cubic metres
Given that side length of the cubical tank = 7 m
We know that volume of cubical tanks is given by
V=x^3V=x
3
where x is the side length of the cube
V=7^3 = 343V=7
3
=343
Other cubical box has also same side length 7 m but the height of water is unknown so let it be x metre.
then volume of the other cubical tank = 7*7*x= 49x
Given that water from cylindrical tank is poured into other two cubical tanks then volume of water in cylinrical tank will be equal to sum of volume of water in both cubical tanks
49x + 343 = 461.58
49x = 461.58 - 343
49x = 118.58
x = 2.42
Hence final answer is 2.42 metres.