A cylindrical piece of paper is 22cm in length and 10 cm in width. it is rolled into a cylinder along its length. find the surface area of this cylinder
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LENGTH OF PAPER = CIRCUMFERENCE OF BASE OF CYLINDER.
2πr = 22
=> r = 22 *7/2*22
=> r =7/2
volume of cylinder = πr2h
=22/7*7/2*7/2*12
=462 cm3.
2πr = 22
=> r = 22 *7/2*22
=> r =7/2
volume of cylinder = πr2h
=22/7*7/2*7/2*12
=462 cm3.
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