Question

② A cylindrical pillar is 50 cm in diameter and 3.5 m in height. Find the cost of painting the curved surface of

the pillar at the rate of ₹ 12.50 per m2​

Answer 1

Answer:

68.68rs

Step-by-step explanation:

Given

Diameter=0.5m

so radius=0.25cm

Height=3.5m

Rate of painting=rs 12.50 per m^2

CSA of cylinder = 2πrh

Putting all the values in formula,

=(2*3.14*0.25*3.5)m^2

=5.495m^2

Cost of painting 1 m^2=12.50

Cost of painting 5.495 m^2= 12.50*5.495

=68.68rs

Answer 2

Given :

• Diameter of Cylindrical Pillar is 50 cm.
• Height of Pillar is 3.5 m

To Find :

• Cost of Painting the C.S.A of pillar at the rate of Rs. 12.50 per m² .

Solution :

$\longmapsto\tt{Radius=\cancel\dfrac{50}{2}=25\:cm}$

$\longmapsto\tt{In\:m=\cancel\dfrac{25}{100}=\dfrac{1}{4}m}$

Using Formula :

$\longmapsto\tt\boxed{C.S.A\:of\:Cylinder=2\pi{rh}}$

Putting Values :

$\longmapsto\tt{{\cancel{2}}\times\dfrac{{\cancel{22}}}{{\cancel{7}}}\times\dfrac{1}{{\cancel{4}}}\times\dfrac{{\cancel{35}}}{10}}$

$\longmapsto{\dfrac{11\times{5}}{10}}$

$\longmapsto\tt{\cancel\dfrac{55}{10}}$

$\longmapsto\tt\bf{5.5\:{m}^{2}}$

Now ,

$\longmapsto\tt{Cost\:of\:1\:{m}^{2}=Rs.12.50}$

$\longmapsto\tt{Cost\:of\:5.5\:{m}^{2}=12.50\times{5.5}}$

$\longmapsto\tt\bf{Rs.68.75}$