Question

a cylindrical pillar is 50cm in diameter and 3.5 cm in height . the cost of painting its curved surface area at the rate of Rs. 12.50 per sq meter is ​​

Answer 1

Answer:

Step-by-step explanation:

Given:

H=3.5 m, R=  

2

50

​  

=25 cm =  

100

25

​  

=0.25 m

⇒CSA=2πrh=(2×  

7

22

​  

×0.25×3.5) m  

2

 

=5.5 m  

2

 

⇒Cost of painting 1 m  

2

 area = Rs.12.50

⇒Cost of painting 5.5 m  

2

 area  

= Rs.5.5×12.50

= Rs.68.75

Answer 2

Answer:

Given:

Given:H=3.5 m, R=

Given:H=3.5 m, R= 2

Given:H=3.5 m, R= 250

Given:H=3.5 m, R= 250

Given:H=3.5 m, R= 250 =25 cm =

Given:H=3.5 m, R= 250 =25 cm = 100

Given:H=3.5 m, R= 250 =25 cm = 10025

Given:H=3.5 m, R= 250 =25 cm = 10025

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2×

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 7

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2 ⇒Cost of painting 1 m

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2 ⇒Cost of painting 1 m 2

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2 ⇒Cost of painting 1 m 2 area = Rs.12.50

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2 ⇒Cost of painting 1 m 2 area = Rs.12.50⇒Cost of painting 5.5 m

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2 ⇒Cost of painting 1 m 2 area = Rs.12.50⇒Cost of painting 5.5 m 2

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2 ⇒Cost of painting 1 m 2 area = Rs.12.50⇒Cost of painting 5.5 m 2 area

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2 ⇒Cost of painting 1 m 2 area = Rs.12.50⇒Cost of painting 5.5 m 2 area = Rs.5.5×12.50

Given:H=3.5 m, R= 250 =25 cm = 10025 =0.25 m⇒CSA=2πrh=(2× 722 ×0.25×3.5) m 2 =5.5 m 2 ⇒Cost of painting 1 m 2 area = Rs.12.50⇒Cost of painting 5.5 m 2 area = Rs.5.5×12.50= Rs.68•75