Question

A cylindrical pillar of diameter 2 meter, having mass 10kg is standing on the ground. How much pressure is exerted by cylindrical pillar on the ground?

Answer 1

Given

• We have a pillar in the shape of a cylinder
• Diameter of the pillar = 2 m
• Mass = 10 kg

To Find

• Pressure applied

Solution

☯ Pressure = Force/Area

☯ Area = πr²

• As the area on which the pillar is standing on will be the bottom surface

☯ Force = ma

━━━━━━━━━━━━━━━━━━━━━━━━━

★ Force Applied :

→ F = ma

→ F = 10 × 9.8

→ F = 98 N

★ Area :

→ Area = πr²

→ Area = 22/7 × 2/2

→ Area = 22/7 m²

━━━━━━━━━━━━━━━━━━━━━━━━━

★ Pressure Applied :

→ Pressure = Force/Area

→ Pressure = 98/(22/7)

→ Pressure = 31.19 Pa

Answer 2

Answer:

Concept :

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. The pressure relative to the surrounding air is known as gauge pressure, also written gauge pressure. Pressure is expressed using a variety of units. Some of these come from dividing a unit of force by a unit of area; the standard unit of pressure in the imperial and U.S. customary systems is the pound-force per square inch (psi), which is equivalent to one newton per square metre (N/m2) in the SI.

Explanation:

Given :

Diameter = 2

Mass = 10kg

To find :

Pressure applied = ?

Solution :

Pressure = Force/Area

Area = π$r^{2}$

Force = ma

Force applied :

F = ma

F = 10×9.8

F = 98N

Area :

A = π$r^{2}$

A = 22/7m^2

Pressure applied :

P = F/A

P = 98/(22/7)

P = 31.19 Pa

#SPJ2