A cylindrical Piller has a diameter of 56cm and is of 35m high.there are 16 pillars around the building.find the cost of painting the curved surface area of all the pillars at the rate of RS/-5.50per 1m square?
Answers
Answer:
Step-by-step explanation:
Cost of painting the 16 pillars of the building=curved surface area of 16 pillars*rate of painting per meter^2
pi*d*h*16*5.50
22/7*0.56*35*16*5.50=$5420.80
Pillar is 50 cm in diameter and 3.5 m high(h)
Convert the diameter (d) to meters (m)
50 cm x 1 m = 0.5 m is the diameter in meters
100 cm
PI = π = 3.14
circumference (C) = πd = 3.14 x 0.5 m = 1.57 m
The cylinder surface area is C x h = 1.57 m x 3.5 m = 5.5 m2
Cost of white washing = 5.5 m2 x Rs 1.25 = Rs 6.88
m2
Gf,
You have to first calculate the surface area of curved surface.
It is given by 2*pi*r*h
in this case it is 2*pi*.25*3.5 = 5.50 sq m
Cost id Rs 1.25 per sq m, so total cost is 5.50*1.25 = Rs 6.9
The surface area of the curved surface of a cylinder is πdh, where d is the diameter and h is the height.
In order to figure out the area, though, you have to have all the numbers in the same units. Since the rate for washing it is per square meter, let's get all the units in meters.
The height is already in meters, so let's convert the diameter to meters. 50 cm = 0.5 m, because there are 100 cm in a meter.
So the area is π * 0.5 * 3.5 which is approximately 5.5 m2. At 1.25 per square meter for washing, the cost for washing is RS 6.875.