Math, asked by bhatias2565, 2 months ago

A cylindrical pipe has an outer diameter of 3 m and an inner diameter of 2 m.Its length is 12 m.It has to be painted on ghe outer and inner surfaces.If the rate of painting is rs 7 per sq. m,find the cost of painting the pipe

Answers

Answered by Agamsain
4

Answer :-

  • Total Cost of Painting the Pipe = 1319.92 Rs

Given :-

  • Inner Diameter of Pipe = 2 m
  • Outer Diameter of Pipe = 3 m
  • Length (Here Height) of Pipe = 12 m
  • Rate of Painting per m² = 7 Rs

To Find :-

  • Total Cost of Painting the Pipe = ?

Explanation :-

In order to Find the Total, First need to find the Inner Radius and Outer Radius of Pipe.

\pink { \boxed { \bf \bigstar \: Radius = \dfrac{Diameter}{2} \: \bigstar }}

\rm \odot \: Inner \: Radius \: (r) = \dfrac{2}{2} = \bold{1 \: m}

\rm \odot \: Outer \: Radius \: (R)= \dfrac{3}{2} = \bold{1.5 \: m}

_____________________

Now, We will Find the Inner CSA and Outer CSA of Pipe.

\green { \boxed { \bf \bigstar \: CSA \: of \: Cylinder = 2 \pi rh \: \bigstar }}

\bf 1. \: Inner \: CSA = 2 \pi rh

\rm : \: \longrightarrow 2 \times \dfrac{22}{7} \times 1 \times 12

\rm : \: \longrightarrow \dfrac{44}{7} \times 12

\rm : \: \longrightarrow \dfrac{528}{7}

\purple { \bf : \: \longrightarrow 75.42 \: m^2 } \qquad \bold{[Approx.]}

\bf 2. \: Outer \: CSA = 2 \pi Rh

\rm : \: \longrightarrow 2 \times \dfrac{22}{7} \times 1.5 \times 12

\rm : \: \longrightarrow \dfrac{44}{7} \times 18

\rm : \: \longrightarrow \dfrac{792}{7}

\purple { \bf : \: \longrightarrow 113.14 \: m^2 } \qquad \bold{[Approx.]}

_____________________

Now, we will Find the Total Area that will be painted.

\orange { \boxed { \bf \bigstar \: Total \: Area \: for \: Painting = Inner \: CSA + Outer \: CSA \: \bigstar }}

\purple { \bf : \: \longrightarrow 188.56 \: m^2 }

_____________________

Now, we will Find the Cost of Painting.

\rm : \: \longrightarrow Cost \: of \: Painting \: 1 \: m^2 = \bold{7 \: R_S}

\rm : \: \longrightarrow Cost \: of \: Painting \: 188.56 \: m^2

        \rm = (188.56 \times 7) \: R_S

       \red { \underline { \boxed { \bf = 1319.92 \: R_S }}}

Hence, the Total Cost Painting the Inner and Outer surfaces of the Pipe is 1319.92 Rs.

Answered by lydiaozho
0

Answer:

Rs. 1320...

Step-by-step explanation:

this the correct answer

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