a cylindrical result with internal radius 5cm and height 10.5cm is full of water a solid of cone base diamtere 7cm and height 6cm is completely immerse in the equator. find the volume of water lenght in the cylindrical result.
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Answer:
Volume of water displaced = Volume of cone
=
3
1
πr
2
h=
3
1
×
7
22
×
2
7
×
2
7
×6
=77cm
3
=0.077 litre
Volume of water left = Volume of cylinder −77cm
3
=πR
2
H−77
=
7
22
×5×5×10.5−77
=825−77
=748cm
3
=0.748 litre
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