A cylindrical road roller made of iron is 1 m long. Its internal diameter is 54 cm and the thickness of the iron sheet used in making the roller is 9 cm. find the mass of the roller, if 1 cm³ of iron has 7.8 gm mass(Use π=3.14)
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Mass of the road roller = 7.943 Kg
Step-by-step explanation:
Inner radius of cylinder r = 54/2 = 27cm
Thickness of the iron = 9
So outer radius R = 36cm
Height of cylinder = 1m
Volume of the iron sheet = Outer volume - inner volume = πR²h - πr²h
= πh (R²-r²)
= πh (R-r)(R+r)
= 22/7 * 1 (9)(36)
= 1018.29 cu.cm
Mass of the road roller = 7.8 * 1018.29 = 7942.66g = 7.943 Kg
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