A cylindrical rod is used to conduct heat energy. If it conducts q cal/sec, then what energy will it conduct if its all linear dimensions are halved?
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Answer:
Given
heat transfer by cylindrical rod is Q cal/s
linear dimension are halved
i.e. length and diameter is reduced to half
Heat conducted is given by
where k= thermal conductivity
A=cross-sectional area
dT=temperature difference
L=length over which heat is flowing
thus A changes
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