Question

A cylindrical rod of copper (Young's modulus of 110 GPa) having a yield strength of 240 MPa is to be subjected to a load of 6660 N. If the length of the rod is 380 mm, what must be the diameter to allow elongation of 0.50 mm?

Answer 1

Answer:

The diameter is 7.64 mm

Explanation:

Force = 6640 N

Length = 380 mm

Elongation = 0.50 mm

Modulus of elasticity = 110 GPa

We need to calculate the area

Using formula of stress

....(I)

....(II)

From equation (I) and (II)

Put the value into the formula

We need to calculate the diameter

Hence, The diameter is 7.64 mm.