a cylindrical roller 2.5 CM length 1.75 CM radius when rolled on a road was found to cover the area of 5500 m square how many revolutions did it make
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HEYA MATE THERE'S YOUR ANSWER☺️☺️
Length/Height of the cylindrical roller=1.75cm
radius of the cylindrical roller=2.5cm
CSA OF THE CYLINDER= 2×22/7×2.5×1.75.
=27.5 cm
THEREFORE total number of revolution= (total area)/CSA of the cylinder
=(5500×100)÷27.5
= 20,000 revolutions
(1 m = 100cm)
HOPE THIS ANS.HELPS..... IF NOT THEN COMMENT BELOW!
Length/Height of the cylindrical roller=1.75cm
radius of the cylindrical roller=2.5cm
CSA OF THE CYLINDER= 2×22/7×2.5×1.75.
=27.5 cm
THEREFORE total number of revolution= (total area)/CSA of the cylinder
=(5500×100)÷27.5
= 20,000 revolutions
(1 m = 100cm)
HOPE THIS ANS.HELPS..... IF NOT THEN COMMENT BELOW!
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