Math, asked by shadowhunter, 1 year ago

a cylindrical roller 2.5 CM length 1.75 CM radius when rolled on a road was found to cover the area of 5500 m square how many revolutions did it make

ppl who answer it will be marked as brainliest by me
answer

Attachments:

shadowhunter: someone pls pls
shadowhunter: please

Answers

Answered by sumitchouhan67p9s83f
1
hope you understand...
Attachments:
Answered by Lazarus
1
HEYA MATE THERE'S YOUR ANSWER☺️☺️
Length/Height of the cylindrical roller=1.75cm
radius of the cylindrical roller=2.5cm
CSA OF THE CYLINDER= 2×22/7×2.5×1.75.
=27.5 cm
THEREFORE total number of revolution= (total area)/CSA of the cylinder
=(5500×100)÷27.5
= 20,000 revolutions
(1 m = 100cm)
HOPE THIS ANS.HELPS..... IF NOT THEN COMMENT BELOW!
Similar questions