Question

a cylindrical roller 2.5m in lenght 1.75m in radius when rolled on road was found to cover the area of 5500m^2 how many revolution did it take​

Answer 1

Given :-

• Length of cylindrical roller (h) = 2.5m
• Radius of roller (r) = 1.75m
• Total surface area of cylinder = 5500m²

To find :-

• Number of revolution

Solution :-

Curved surface area of cylinder

→ 2πrh

→ 2 × 22/7 × 1.75 × 2.5

→ 2 × 22 × 0.25 × 2.5

→ 44 × 0.625

→ 27.5 m²

One revolution = Curved surface area of cylinder

Now, total number of revolution

→ total surface area of roller/curved surface area of roller

→ 5500/27.5

→ 200

Hence,

• Total number of revolution is 200

Extra Information :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

Answer 2

Answer:

I am in 10 standard .........