A cylindrical roller 2.5m in length 1.5 in radius rolled on a road was found to covet the area of 16500m^2. How many revolutions does it make?
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Answered by
94
700 is the answer...
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Answered by
71
hiii!!!
here's ur answer...
given:-
height (length) of the cylindrical roller=2.5m
radius=1.5m
CSA (lateral surface area) of the cylindrical roller=2πrh
=2×22/7×1.5×2.5
=165/7m²
area of the road covered by the roller=16500m²
therefore no. of revolutions it took to cover the area= 16500/1×7/165
=100×7
=700
hence, it took 700 revolutions to cover 16500m².
hope this helps...
(^^)
here's ur answer...
given:-
height (length) of the cylindrical roller=2.5m
radius=1.5m
CSA (lateral surface area) of the cylindrical roller=2πrh
=2×22/7×1.5×2.5
=165/7m²
area of the road covered by the roller=16500m²
therefore no. of revolutions it took to cover the area= 16500/1×7/165
=100×7
=700
hence, it took 700 revolutions to cover 16500m².
hope this helps...
(^^)
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