A cylindrical roller 25m length 7m in radius when rolled on a road was found to cover an area of 5500m.how many revolitions did it make
Answers
Answered by
9
Answer:
... for one revolution area covered
is 2 πrx25=2x22x7x25/7=1100m2
Total distance moved=5500m2
No. of revolutions = 5500/110=5
Answered by
33
Given :
Height of cylinder = 25 m
Radius of cylinder = 7 m
Area = 5500 m²
Find :
Number of revolutions.
Solution :
Curved surface area of cylinder = Distance travelled in one turn
2πrh = 5500
Now,
Distance travelled = "n" number of turms
So,
→ n × 2πrh = 5500
→ n × 2 × 22/7 × 7 × 25 = 5500
→ n × 44 × 25 = 5500
→ n × 1100 = 5500
→ n = 5
∴ The cylindrical roller makes 5 turns.
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