A cylindrical roller is 2m in length with a radius of 50 cm. how many revolutions does it have to make to level an area of 528m square
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=> curved Surface Area = 2πrh
=> CSA = 2 x 22/7 x 0.5 x 2
=> CSA = 6.28 m^2
=> Revolution = Area to be Covered/ CSA
=> Revolution = (528/6.28) m^2/m^2
=> Revolution = 83.5
Hence,
Roller will take Revolution = 83.5
=> CSA = 2 x 22/7 x 0.5 x 2
=> CSA = 6.28 m^2
=> Revolution = Area to be Covered/ CSA
=> Revolution = (528/6.28) m^2/m^2
=> Revolution = 83.5
Hence,
Roller will take Revolution = 83.5
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